问题描述：在使用request.GetResponse时，如果是400错误，将抛出异常信息，而获取不到返回内容，所以返回的内容只能在catch上面获取，转载于

http://blog.csdn.net/ahywg/article/details/26267113

解决方法：

 

WebRequest request = WebRequest.Create("网址");

Stream stream=null;  try  {   using (WebResponse response = request.GetResponse())   {    	stream=response.GetResponseStream();   }  }  

catch (WebException e)  {

stream=e.Response.GetResponseStream();

}